2(x-6)^2+x^2=x(x+48)-42x

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Solution for 2(x-6)^2+x^2=x(x+48)-42x equation:



2(x-6)^2+x^2=x(x+48)-42x
We move all terms to the left:
2(x-6)^2+x^2-(x(x+48)-42x)=0
We calculate terms in parentheses: -(x(x+48)-42x), so:
x(x+48)-42x
We add all the numbers together, and all the variables
-42x+x(x+48)
We multiply parentheses
x^2-42x+48x
We add all the numbers together, and all the variables
x^2+6x
Back to the equation:
-(x^2+6x)
We get rid of parentheses
x^2-x^2+2(x-6)^2-6x=0
We add all the numbers together, and all the variables
-6x+2(x-6)^2=0

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